Apresentação em tema: "Correção dos exercícios de engenharia do conhecimento em Prolog"— Transcrição da apresentação:
1Correção dos exercícios de engenharia do conhecimento em Prolog Jacques Robin, DI-UFPE
2Estudo de caso: a terrível novela Requisitos em Inglês 1. A soap opera is a TV show whose characters include a husband, a wife and a mailman such that:2. the wife and the mailman blackmail each other3. everybody is either alcoholic, drug addict or gay4. Dick is gay, Jane is alcoholic and Harry is a drug addict5. the wife is always an alcoholic and the long-lost sister of her husband6. the husband is always called Dick and the lover of the mailman7. the long-lost sister of any gay is called either Jane or Cleopatra8. Harry is the lover of every gay9. Jane blackmails every drug addicted lover of Dick10. soap operas are invariably terrible!0. Who are the characters of a terrible TV show?
5Estudo de caso: o BD acadêmico Requisitos em Inglês 1. Bob is 40 and the manager of the CS department.2. His assistants are John and Sally.3. Mary’s highest degree is an MS and she works at the CS department.4. She co-authored with her boss and her friends, John and Sally, a paper published in the Journal of the ACM.5. Phil is a faculty, who published a paper on F-Logic at a Conference of the ACM, jointly with Mary and Bob.6. Every faculty is a midaged person who writes article, makes in the average $50,000 a year and owns a degree of some kind, typically a PhD.7. One is considered midage if one is between 30 and 50 years old.8. A faculty’s boss is both a faculty and a manager.9. Friends and children of a person are also persons.10. Every department has a manager who is an employee and assistants who are both employees and students11. A boss is an employee who is the manager of another employee of the same department.12. A joint work is a paper that is written by two faculties13. There are three types of papers: technical reports, journal papers and conference papers0a: Who are the midaged employees of the CS department and who are their boss?0b: Who published jointly with Mary in the Journal of the ACM?0c: Where did Mary published joint work with Phil?
6Correção do exercício 3: O banco de dados acadêmico em Prolog 1/ fatos ground person(bob).age(bob,40).works(bob,cs,faculty).manager(cs,bob).dept(cs).works(john,cs,assistant).study(john,cs).works(sally,cs,assistant).study(sally,cs).hiDeg(mary,ms).works(mary,cs,faculty).friends(mary,bob).friends(mary,sally).works(phil,cs,faculty).degree(phd).degree(ms).journal(jacm).conf(cacm).article(flogic,[john,sally,mary,bob],jacm).article(florid,[phil,mary,bob],cacm).
7Correção do exercício 3: O banco de dados acadêmico em Prolog 2/ regras de dedução hiDeg(F,phd) :- works(F,_,faculty), not hiDeg(F,ms).salary(P,5000) :- works(F,_,faculty), not salary(F,_).midaged(F) :- age(F,A), !, integer(A), A >= 30, A =< 50.midaged(F) :- works(F,_,faculty).works(B,D,faculty) :- manager(D,B), works(E,D,faculty), !.activity(F,paperWriting) :- works(F,_,faculty).person(P2) :- friends(P1,P2), person(P1).person(C) :- parent(A,C), person(A).person(P) :- study(P,D), dept(D).person(P) :- works(P,_,D), dept(D).works(S,D,assistant) :- study(S,D), dept(D), works(S,D,_), !.works(M,D,_) :- manager(M,D).boss(B,E) :- manager(D,B), works(E,D,_).jointWork(W,F1,F2,P) :- works(F1,_,faculty), works(F2,_,faculty), F1 \= F2, report(W,Fl,P), member(F1,Fl), member(F2,Fl).member(H,[H|T]).member(X,[H|T]) :- member(X,T).report(T,Al,J) :- article(T,Al,J), journal(J).report(T,Al,C) :- article(T,Al,C), conf(C).report(T,Al,D) :- techrep(T,Al,D), dept(D).
8Correção do exercício 3: O banco de dados acadêmico em Prolog 3/ consultas midagedWorkerOf(E,D) :- works(E,D,_), midaged(E).bossOfMidagedWorkerOf(B,D) :- midagedWorkerOf(E,D), boss(B,E).? setof(E,midagedWorkerOf(E,cs),Le),setof(B,bossOfMidagedWorkerOf(B,cs),Lb).E = _20, Le = [bob,mary],B = _51, Lb = [bob];no.? setof(F,jointWork(_,F,mary,jacm),Lf).F = _20, Lf = [bob];? setof(P,jointWork(_,phil,mary,P),Lp).P = _20, Lp = [cacm];no
9Correção do exercício 4: O banco de dados acadêmico em L1 1/ formulas ground
10Correção do exercício 4: O banco de dados acadêmico em L1 2/ formulas quantificadas
11Correção do exercício 4: O banco de dados acadêmico em L1 3/ consultas
12Estudo de caso: A curiosidade matou o gato? Requisitos em inglês1. Jack owns a dog.2. Every dog owner is an animal lover.3. No animal lover kills an animal.4. Either Jack or curiosity killed Tuna5. Tuna is a catA. Did curiosity kill the cat?B. Quem matou o gato?Em L11. $x Dog(x) Ù Owns(Jack,x)2. "x ($y Dog(y) Ù Owns(x,y)) Þ AnimalLover(x)3. "x,y (AnimalLover(x) Ù Animal(y)) Þ ØKills(x,y)4. (Kills(Jack, Tuna) ÚKills(Curiosity, Tuna)) Ù Ø(Kills(Jack, Tuna) ÙKills(Curiosity, Tuna))5. Cat(Tuna)6. "x Cat(x) Þ Animal(x)0. Kills(Curiosity,Tuna)B. X, Kills(X,Tuna)